4y^2-y+12=0

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Solution for 4y^2-y+12=0 equation: 



4y^2-y+12=0

We add all the numbers together, and all the variables

4y^2-1y+12=0

a = 4; b = -1; c = +12;
Δ = b2-4ac
Δ = -12-4·4·12
Δ = -191
Delta is less than zero, so there is no solution for the equation

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